What is the directrix y=9x^2+6x+1 ?

The directrix y=9x^2+6x+1 is y=-1/36

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directrix y=9x^2+6x+1

directrix

y = 9 x^{2} + 6 x + 1

y = - \frac{1}{36}

Solution steps

Rewrite

y = 9 x^{2} + 6 x + 1

in the standard form

4 \cdot \frac{1}{36} (y - 0) = (x - (- \frac{1}{3}))^{2}

(h, k) = (- \frac{1}{3}, 0), p = \frac{1}{36}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(- \frac{1}{3}, 0)

y-coordinate

y = 0 - p

y = 0 - \frac{1}{36}

Refine

y = - \frac{1}{36}

x^{2} + 4 x + 7

y = 2 x^{2} - 6 x + 4

\frac{( x - 5 ) ( x - 10 )}{50}

2 x^{2} - 12 x + 14 - 14 y = 0

(4 - x)^{2}