What is the directrix x=(-1)/4 (y+2)^2 ?

The directrix x=(-1)/4 (y+2)^2 is x=1

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directrix x=(-1)/4 (y+2)^2

directrix

x = \frac{- 1}{4} (y + 2)^{2}

x = 1

Solution steps

Rewrite

x = \frac{- 1}{4} (y + 2)^{2}

in the standard form:

4 (- 1) (x - 0) = (y - (- 2))^{2}

(h, k) = (0, - 2), p = - 1

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(0, - 2)

x-coordinate

x = 0 - p

x = 0 - (- 1)

Refine

x = 1

x^{2} - x - 56

y^{2} = 4 a x

y^{2} - 2 y - 4 x + 9 = 0

\frac{1}{3} x^{2} - \frac{8}{3} x + \frac{1}{3}

2 x^{2} - 7 x + 15