What is the directrix-x^2-4x-3 ?

The directrix-x^2-4x-3 is y= 5/4

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directrix-x^2-4x-3

directrix

- x^{2} - 4 x - 3

y = \frac{5}{4}

Solution steps

Rewrite

y = - x^{2} - 4 x - 3

in the standard form

4 (- \frac{1}{4}) (y - 1) = (x - (- 2))^{2}

(h, k) = (- 2, 1), p = - \frac{1}{4}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(- 2, 1)

y-coordinate

y = 1 - p

y = 1 - (- \frac{1}{4})

Refine

y = \frac{5}{4}

y^{2} = - 7 x

x = y^{2} - 4

y = x^{2} + 5 x - 14

(x + 1)^{2} = - 3 (y - 6)

- 3 (x - 1)^{2}