What is the axis y=-x^2-4x-2 ?

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axis y=-x^2-4x-2

axis

y = - x^{2} - 4 x - 2

x = - 2

Solution steps

y = - x^{2} - 4 x - 2

Rewrite

y = - x^{2} - 4 x - 2

in the standard form

4 (- \frac{1}{4}) (y - 2) = (x - (- 2))^{2}

Therefore parabola properties are:

(h, k) = (- 2, 2), p = - \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = - 2

y = x^{2} - 3 x^{2}

y = 4 x^{2}

y = 4 x^{2} - 4 x^{1}

y = x^{2} - 5 x + 6

y = x^{2} - 10 x - 4