What is (x-2)^2+(y-3)^2=64 ?

The solution to (x-2)^2+(y-3)^2=64 is Circle with (a,b)=(2,3),r=8

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(x-2)^2+(y-3)^2=64

(x - 2)^{2} + (y - 3)^{2} = 64

(a, b) = (2, 3), r = 8

Solution steps

(x - 2)^{2} + (y - 3)^{2} = 64

Rewrite

(x - 2)^{2} + (y - 3)^{2} = 64

in the form of the standard circle equation

(x - 2)^{2} + (y - 3)^{2} = 8^{2}

Therefore the circle properties are:

(a, b) = (2, 3), r = 8

4 x^{2} - 9 y^{2} = 36

4 x^{2} - 9 y^{2} = 36

f (x) = x^{2} - 8

x^{2} - 24 y + 48 = 0

81 x^{2} - 1296 x + 16 y^{2} + 64 y = - 3952

What is (x-2)^2+(y-3)^2=64 ?
The solution to (x-2)^2+(y-3)^2=64 is Circle with (a,b)=(2,3),r=8