What is the axis y=1-x^2 ?

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axis y=1-x^2

axis

y = 1 - x^{2}

x = 0

Solution steps

y = 1 - x^{2}

Rewrite

y = 1 - x^{2}

in the standard form:

4 (- \frac{1}{4}) (y - 1) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 1), p = - \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 0

y = 2 x^{2} - 1 - (5 x - 6)

y = 2 (x + 1)^{2}

y = a x^{2}

y = + x^{2} + 3 x - 4

y = x^{2} + 8 x + 15