What is the axis y=-1.25x^2+50x+4000 ?

The axis y=-1.25x^2+50x+4000 is x=20

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axis y=-1.25x^2+50x+4000

axis

y = - 1.25 x^{2} + 50 x + 4000

x = 20

Solution steps

y = - 1.25 x^{2} + 50 x + 4000

Rewrite

y = - 1.25 x^{2} + 50 x + 4000

in the standard form

4 (- 0.2) (y - 4500) = (x - 20)^{2}

Therefore parabola properties are:

(h, k) = (20, 4500), p = - 0.2

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 20

y = x^{2} - 5 x - 6

y = 2 x^{2} + 5 x + 2

y = - 3 x^{2} - 12 x - 9

y = x^{2} - 10 x + 24

y = x^{2} - 5 x 3