What is the axis (x^2}{16}+\frac{y^2)/9 =1 ?

The axis (x^2}{16}+\frac{y^2)/9 =1 is semi-major axis a=4, semi-minor axis b=3

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axis (x^2}{16}+\frac{y^2)/9 =1

axis

\frac{x ^{2}}{16} + \frac{y ^{2}}{9} = 1

semi - major axis a = 4, semi - minor axis b = 3

Solution steps

\frac{x ^{2}}{16} + \frac{y ^{2}}{9} = 1

Rewrite

\frac{x ^{2}}{16} + \frac{y ^{2}}{9} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{4 ^{2}} + \frac{( y - 0 ) ^{2}}{3 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 4, b = 3

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 4, b = 3

3 x^{2} + 8 y = 0

4 x^{2} - 9 y^{2} = 36

y \leq - 3 x^{2} + 1

f (x) = x^{2} + 2 x - 3

- (x + 3)^{2} - 1

What is the axis (x^2}{16}+\frac{y^2)/9 =1 ?
The axis (x^2}{16}+\frac{y^2)/9 =1 is semi-major axis a=4, semi-minor axis b=3