What is the axis y=6x^2-7x-3 ?

The axis y=6x^2-7x-3 is x= 7/12

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axis y=6x^2-7x-3

axis

y = 6 x^{2} - 7 x - 3

x = \frac{7}{12}

Solution steps

y = 6 x^{2} - 7 x - 3

Rewrite

y = 6 x^{2} - 7 x - 3

in the standard form

4 \cdot \frac{1}{24} (y - (- \frac{121}{24})) = (x - \frac{7}{12})^{2}

Therefore parabola properties are:

(h, k) = (\frac{7}{12}, - \frac{121}{24}), p = \frac{1}{24}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = \frac{7}{12}

y = x^{2} - x + 5

y = x^{2} - 12 x + 46

18 x^{2} - 64 x - 14 y + 150 = 0

y = x^{2} + 4

y^{2} = 8 x