What is the axis y^2=x-3 ?

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axis y^2=x-3

axis

y^{2} = x - 3

y = 0

Solution steps

y^{2} = x - 3

Rewrite

y^{2} = x - 3

in the standard form:

4 \cdot \frac{1}{4} (x - 3) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (3, 0), p = \frac{1}{4}

Parabola is of the form

4 p (x - h) = (y - k)^{2}

and is symmetric around the

x

-axis

Axis of symmetry is a line parallel to the

x

-axis which intersects the vertex:

y = 0

y = 4 (x + 1)^{2} - 3

y = x^{2} + 8 x + 12

x^{2} + 8 y + 2 x - 23 = 0

y = x^{2} - 4 x + 5

3 y^{2} = 24 x