What is the axis y^2=-8x ?

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axis y^2=-8x

axis

y^{2} = - 8 x

y = 0

Solution steps

y^{2} = - 8 x

Rewrite

y^{2} = - 8 x

in the standard form:

4 (- 2) (x - 0) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = - 2

Parabola is of the form

4 p (x - h) = (y - k)^{2}

and is symmetric around the

x

-axis

Axis of symmetry is a line parallel to the

x

-axis which intersects the vertex:

y = 0

y = 3 x^{2} - 12 x + 8

x^{2} = 8 y

y = x^{2} + 4 x - 45

y = (x - 3)^{2} - 4

(x + 6)^{2} = 12 (y + 1)