What is the axis y=3x^2+9x+9 ?

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axis y=3x^2+9x+9

axis

y = 3 x^{2} + 9 x + 9

x = - \frac{3}{2}

Solution steps

y = 3 x^{2} + 9 x + 9

Rewrite

y = 3 x^{2} + 9 x + 9

in the standard form

4 \cdot \frac{1}{12} (y - \frac{9}{4}) = (x - (- \frac{3}{2}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{3}{2}, \frac{9}{4}), p = \frac{1}{12}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = - \frac{3}{2}

y = 0.07 x^{2} + 20 x + 350

y = (x - 9)^{2} - 2

y^{2} - 8 x - 16 = 0

(x + 7)^{2} = 5 (y + 3)

x \leq + y^{2}