What is the axis y=-x^2+80x-700 ?

The axis y=-x^2+80x-700 is x=40

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axis y=-x^2+80x-700

axis

y = - x^{2} + 80 x - 700

x = 40

Solution steps

y = - x^{2} + 80 x - 700

Rewrite

y = - x^{2} + 80 x - 700

in the standard form

4 (- \frac{1}{4}) (y - 900) = (x - 40)^{2}

Therefore parabola properties are:

(h, k) = (40, 900), p = - \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 40

y = \frac{1}{5} (x - 3)^{2} - 5

y = x^{2} - 2 x + 4

y = x^{2} - 16

y = 9 x^{2} - 4

(x + 3)^{2} = - y