What is the axis y^2=28x ?

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axis y^2=28x

axis

y^{2} = 28 x

y = 0

Solution steps

y^{2} = 28 x

Rewrite

y^{2} = 28 x

in the standard form:

4 \cdot 7 (x - 0) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = 7

Parabola is of the form

4 p (x - h) = (y - k)^{2}

and is symmetric around the

x

-axis

Axis of symmetry is a line parallel to the

x

-axis which intersects the vertex:

y = 0

y = 0.00225 x^{2} + 5999.9325 x + 0.50625

y = \frac{4 x ^{2} + 12 x - 15}{3}

(x + 2)^{2} = - 12 (y - 5)

y = x (x - 4)

y^{2} - x + 8 y + 13 = 0