What is the axis y=x^2-6x+10 ?

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axis y=x^2-6x+10

axis

y = x^{2} - 6 x + 10

x = 3

Solution steps

y = x^{2} - 6 x + 10

Rewrite

y = x^{2} - 6 x + 10

in the standard form

4 \cdot \frac{1}{4} (y - 1) = (x - 3)^{2}

Therefore parabola properties are:

(h, k) = (3, 1), p = \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 3

y = - 0.23 x^{2} + 1.87 x + 1.5

y = - 3 x^{2} - 42 x - 22

x^{2} = 12 y

y = 4 x^{2} - 2 x

y = x^{2} + 4 x + 5