What is the axis x^2-y=0 ?

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axis x^2-y=0

axis

x^{2} - y = 0

x = 0

Solution steps

x^{2} - y = 0

Rewrite

x^{2} - y = 0

in the standard form:

4 \cdot \frac{1}{4} (y - 0) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 0

y = 2250 (0.015 - 0.001 x)^{2} + 6000 x

y - 2 = 3 (x - 5)^{2}

y = 160 x - 16 x^{2}

x^{2} + 6 x + 3 y + 2 = 0

y = - 2 x^{2} - 3 x + 5