What is the axis y=8-5x+x^2 ?

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

axis y=8-5x+x^2

axis

y = 8 - 5 x + x^{2}

x = \frac{5}{2}

Solution steps

y = 8 - 5 x + x^{2}

Rewrite

y = 8 - 5 x + x^{2}

in the standard form

4 \cdot \frac{1}{4} (y - \frac{7}{4}) = (x - \frac{5}{2})^{2}

Therefore parabola properties are:

(h, k) = (\frac{5}{2}, \frac{7}{4}), p = \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = \frac{5}{2}

y = 5 x^{2} - 7

y = x^{2} - 2 x + 5

x = (y + 2)^{2}

y = + x^{2} + 14 x + 45

y = 1.4 x^{2} + 2 x + 1