What is x^2+y^2+6x-4y-23=0 ?

The solution to x^2+y^2+6x-4y-23=0 is Circle with (a,b)=(-3,2),r=6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^2+y^2+6x-4y-23=0

x^{2} + y^{2} + 6 x - 4 y - 23 = 0

(a, b) = (- 3, 2), r = 6

Solution steps

x^{2} + y^{2} + 6 x - 4 y - 23 = 0

Rewrite

x^{2} + y^{2} + 6 x - 4 y - 23 = 0

in the form of the standard circle equation

(x - (- 3))^{2} + (y - 2)^{2} = 6^{2}

Therefore the circle properties are:

(a, b) = (- 3, 2), r = 6

y^{2} = - 8 x

16 y^{2} - 32 y - 9 x^{2} - 18 x = 137

4 x^{2} + 4 y^{2} - 4 x + 2 y - 1 = 0

25 x^{2} + 16 y^{2} = 400

\frac{x ^{2}}{9} - \frac{y ^{2}}{4} = 1

What is x^2+y^2+6x-4y-23=0 ?
The solution to x^2+y^2+6x-4y-23=0 is Circle with (a,b)=(-3,2),r=6