What is the axis x=y^2-6 ?

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axis x=y^2-6

axis

x = y^{2} - 6

y = 0

Solution steps

x = y^{2} - 6

Rewrite

x = y^{2} - 6

in the standard form:

4 \cdot \frac{1}{4} (x - (- 6)) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (- 6, 0), p = \frac{1}{4}

Parabola is of the form

4 p (x - h) = (y - k)^{2}

and is symmetric around the

x

-axis

Axis of symmetry is a line parallel to the

x

-axis which intersects the vertex:

y = 0

y = 40 (x - 1) + 6 - 33 (1 - \frac{x}{0.4})^{2}

y = \frac{1}{4} (x - 10)^{2} - 1

y = x^{2} + x - 10

y = x^{2} - 8 x + 19

y = x^{2} + 4 x + 3