What is the axis x=+(y-3)^2 ?

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axis x=+(y-3)^2

axis

x = + (y - 3)^{2}

y = 3

Solution steps

x = (y - 3)^{2}

Rewrite

x = (y - 3)^{2}

in the standard form:

4 \cdot \frac{1}{4} (x - 0) = (y - 3)^{2}

Therefore parabola properties are:

(h, k) = (0, 3), p = \frac{1}{4}

Parabola is of the form

4 p (x - h) = (y - k)^{2}

and is symmetric around the

x

-axis

Axis of symmetry is a line parallel to the

x

-axis which intersects the vertex:

y = 3

y = 0.5 x^{2} - 3 x + 5

y = 4 x^{2} - 7 x + 7

y = 5 x^{2} - 3 x + 3

y = 2 x^{2} + 3 x - 1

y = 4 - (x - 3)^{2}