What is the axis x=(-y-1)(y+3) ?

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axis x=(-y-1)(y+3)

axis

x = (- y - 1) (y + 3)

y = - 2

Solution steps

x = (- y - 1) (y + 3)

Rewrite

x = (- y - 1) (y + 3)

in the standard form

4 (- \frac{1}{4}) (x - 1) = (y - (- 2))^{2}

Therefore parabola properties are:

(h, k) = (1, - 2), p = - \frac{1}{4}

Parabola is of the form

4 p (x - h) = (y - k)^{2}

and is symmetric around the

x

-axis

Axis of symmetry is a line parallel to the

x

-axis which intersects the vertex:

y = - 2

y = 2 (x - 1)^{2}

x^{2} + 7 x + 10

y^{2} - 4 y - 8 x - 12 = 0

y^{2} = 16 x - 8

y = x^{2} + 10 x - 11