What is the axis y=4-(x-1)^2 ?

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

axis y=4-(x-1)^2

axis

y = 4 - (x - 1)^{2}

x = 1

Solution steps

y = 4 - (x - 1)^{2}

Rewrite

y = 4 - (x - 1)^{2}

in the standard form:

4 (- \frac{1}{4}) (y - 4) = (x - 1)^{2}

Therefore parabola properties are:

(h, k) = (1, 4), p = - \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 1

y = x^{2} - 10 x - 24

+ (y - 2) = 3 (x - 5)^{2}

y = (x + 2)^{4}

x = (y + 1) (2 y + 5)

6 x^{2} - 7 x + y = 0