What is the axis y=2x^2+4x-3 ?

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axis y=2x^2+4x-3

axis

y = 2 x^{2} + 4 x - 3

x = - 1

Solution steps

y = 2 x^{2} + 4 x - 3

Rewrite

y = 2 x^{2} + 4 x - 3

in the standard form

4 \cdot \frac{1}{8} (y - (- 5)) = (x - (- 1))^{2}

Therefore parabola properties are:

(h, k) = (- 1, - 5), p = \frac{1}{8}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = - 1

y = 2 x^{2} + 4 x - 6

y = (\frac{1}{2} x + 4)^{2}

y = 2 x^{2} - 8

y = x^{2} - 2 x - 9

x^{2} - 6 x - 5 y - 1 = 0