What is the axis y=12x(x-4) ?

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axis y=12x(x-4)

axis

y = 12 x (x - 4)

x = 2

Solution steps

y = 12 x (x - 4)

Rewrite

y = 12 x (x - 4)

in the standard form

4 \cdot \frac{1}{48} (y - (- 48)) = (x - 2)^{2}

Therefore parabola properties are:

(h, k) = (2, - 48), p = \frac{1}{48}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 2

x - 2 = (y - 1)^{2}

y = 6 x^{2} - 29 x - 5

y = 3 x^{2} + x - 6

x^{2} + 4 x - 4 y + 5 = 0

x = 7 y^{2}