What is the axis y>= x^2 ?

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axis y>= x^2

axis

y \geq x^{2}

x = 0

Solution steps

y \geq x^{2}

Rewrite

y \geq x^{2}

in the standard form:

4 \cdot \frac{1}{4} (y - 0) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 0

y = 5 (x + 2)^{2} - 3

y = - \frac{1}{2} x^{2} - 5 x - \frac{15}{2}

x = y - y^{2}

y = x^{2} - 5 x

y = 600 - 10 x + 0.25 x^{2}