What is (x^2)/(4^2)+(y^2)/(3^2)=1 ?

The solution to (x^2)/(4^2)+(y^2)/(3^2)=1 is Ellipse with (h,k)=(0,0),a=4,b=3

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(x^2)/(4^2)+(y^2)/(3^2)=1

\frac{x ^{2}}{4 ^{2}} + \frac{y ^{2}}{3 ^{2}} = 1

(h, k) = (0, 0), a = 4, b = 3

Solution steps

\frac{x ^{2}}{4 ^{2}} + \frac{y ^{2}}{3 ^{2}} = 1

Rewrite

\frac{x ^{2}}{4 ^{2}} + \frac{y ^{2}}{3 ^{2}} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{4 ^{2}} + \frac{( y - 0 ) ^{2}}{3 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 4, b = 3

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 4, b = 3

x^{2} + (y - 2)^{2} = 4

x^{2} - 6 x + 8 y - 31 = 0

36 x^{2} + 25 y^{2} = 900

y - x^{2} = 0

\frac{x ^{2}}{9} - \frac{y ^{2}}{16} = 1

What is (x^2)/(4^2)+(y^2)/(3^2)=1 ?
The solution to (x^2)/(4^2)+(y^2)/(3^2)=1 is Ellipse with (h,k)=(0,0),a=4,b=3