What is the axis y=-0.00004x^2-0.00105x+1.055 ?

The axis y=-0.00004x^2-0.00105x+1.055 is x=-(0.00105)/(0.00008)

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axis y=-0.00004x^2-0.00105x+1.055

axis

y = - 0.00004 x^{2} - 0.00105 x + 1.055

x = - \frac{0.00105}{0.00008}

Solution steps

y = - 0.00004 x^{2} - 0.00105 x + 1.055

Rewrite

y = - 0.00004 x^{2} - 0.00105 x + 1.055

in the standard form

4 (- 6249.99999 \dots) (y - 0) = (x - (- \frac{0.00105}{0.00008}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{0.00105}{0.00008}, 0), p = - 6249.99999 \dots

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = - \frac{0.00105}{0.00008}

(x + 3)^{2} = 5 y - 8

x = \frac{( y - 3 ) ^{2}}{8} + 5

y = x^{2} - 42 + 10 x

(x + 9)^{2} = - 44 (y - 1)

y = - 2 x^{2} + 12 x - 14

What is the axis y=-0.00004x^2-0.00105x+1.055 ?
The axis y=-0.00004x^2-0.00105x+1.055 is x=-(0.00105)/(0.00008)