What is the axis y=8x-2x^2 ?

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axis y=8x-2x^2

axis

y = 8 x - 2 x^{2}

x = 2

Solution steps

y = 8 x - 2 x^{2}

Rewrite

y = 8 x - 2 x^{2}

in the standard form

4 (- \frac{1}{8}) (y - 8) = (x - 2)^{2}

Therefore parabola properties are:

(h, k) = (2, 8), p = - \frac{1}{8}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 2

y = - 6 x^{2} + 600 x - 5726

y > 2 x^{2} + 5

(x + 4)^{2} = - 8 (y - 3)

y = (x + 5)^{2} + 3

y = 3 x^{2} + 4 x - 5