What is the axis x=(2y-1)(5y-6) ?

The axis x=(2y-1)(5y-6) is y= 17/20

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axis x=(2y-1)(5y-6)

axis

x = (2 y - 1) (5 y - 6)

y = \frac{17}{20}

Solution steps

x = (2 y - 1) (5 y - 6)

Rewrite

x = (2 y - 1) (5 y - 6)

in the standard form

4 \cdot \frac{1}{40} (x - (- \frac{49}{40})) = (y - \frac{17}{20})^{2}

Therefore parabola properties are:

(h, k) = (- \frac{49}{40}, \frac{17}{20}), p = \frac{1}{40}

Parabola is of the form

4 p (x - h) = (y - k)^{2}

and is symmetric around the

x

-axis

Axis of symmetry is a line parallel to the

x

-axis which intersects the vertex:

y = \frac{17}{20}

y^{2} + 4 x - 8 y + 12 = 0

y = 2 x^{2} - x - 6

y = 8 x^{2} + 22 x - 13

y = \frac{( x + 7 ) ^{2}}{9}

y = + 4 x^{2} + 7