What is the axis y=-5x^2-40x-77 ?

The axis y=-5x^2-40x-77 is x=-4

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axis y=-5x^2-40x-77

axis

y = - 5 x^{2} - 40 x - 77

x = - 4

Solution steps

y = - 5 x^{2} - 40 x - 77

Rewrite

y = - 5 x^{2} - 40 x - 77

in the standard form

4 (- \frac{1}{20}) (y - 3) = (x - (- 4))^{2}

Therefore parabola properties are:

(h, k) = (- 4, 3), p = - \frac{1}{20}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = - 4

y = 3 x^{2} + 9

\Rightarrow y = 0.5 k x^{2}

6 x^{2} + 12 y - 18 = 0

y = x^{2} + 6 x + 11

y^{2} = - 12 x