What is the axis (x-3)^2=20(y+119/20) ?

The axis (x-3)^2=20(y+119/20) is x=3

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axis (x-3)^2=20(y+119/20)

axis

(x - 3)^{2} = 20 (y + \frac{119}{20})

x = 3

Solution steps

(x - 3)^{2} = 20 (y + \frac{119}{20})

Rewrite

(x - 3)^{2} = 20 (y + \frac{119}{20})

in the standard form:

4 \cdot 5 (y - (- \frac{119}{20})) = (x - 3)^{2}

Therefore parabola properties are:

(h, k) = (3, - \frac{119}{20}), p = 5

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 3

x > - (y + 4)^{2}

y = - x^{2} + 2 x + 10

y = 5 x^{2} + x - 4

y = + \frac{17}{4} (x + 2)^{2}

y = + 2 x^{2} + x - 1