What is the axis y=-1/11 (x+5)^2+5 ?

The axis y=-1/11 (x+5)^2+5 is x=-5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

axis y=-1/11 (x+5)^2+5

axis

y = - \frac{1}{11} (x + 5)^{2} + 5

x = - 5

Solution steps

y = - \frac{1}{11} (x + 5)^{2} + 5

Rewrite

y = - \frac{1}{11} (x + 5)^{2} + 5

in the standard form:

4 (- \frac{11}{4}) (y - 5) = (x - (- 5))^{2}

Therefore parabola properties are:

(h, k) = (- 5, 5), p = - \frac{11}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = - 5

y = - 2 x + x (x - 2) - 2 x (x - 1) - (x - 3)

y = x^{2} - 4 x - 4

x = 4 (y + 6) + 3 (2 + y + 3 y^{2}) - 2 y^{2}

y = (x + 1) (2 x + 5)

y = \frac{1}{4} x^{2} - 3 x - 7