What is the axis y=49x^2-64 ?

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axis y=49x^2-64

axis

y = 49 x^{2} - 64

x = 0

Solution steps

y = 49 x^{2} - 64

Rewrite

y = 49 x^{2} - 64

in the standard form:

4 \cdot \frac{1}{196} (y - (- 64)) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, - 64), p = \frac{1}{196}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 0

y = 3 x^{2} - 3 x + 2

(x - 2)^{2} = - (y - 4)

y = x^{2} + 4 x + 10

y = - 2 x^{2} - 12 x - 23

y = x^{2} + 5 x - 84