What is the axis y=x^2-3x-40 ?

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axis y=x^2-3x-40

axis

y = x^{2} - 3 x - 40

x = \frac{3}{2}

Solution steps

y = x^{2} - 3 x - 40

Rewrite

y = x^{2} - 3 x - 40

in the standard form

4 \cdot \frac{1}{4} (y - (- \frac{169}{4})) = (x - \frac{3}{2})^{2}

Therefore parabola properties are:

(h, k) = (\frac{3}{2}, - \frac{169}{4}), p = \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = \frac{3}{2}

x = (3 - y)^{2}

y = 7 x^{2} - 8

y = (x - 2)^{2} + 1

y = 3 x^{2} + 5 x

y = 3 - 5 (x + 1)^{2}