What is the axis x=-2y+y(y-2)-2y(y-1)-(y-3) ?

The axis x=-2y+y(y-2)-2y(y-1)-(y-3) is y=-3/2

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axis x=-2y+y(y-2)-2y(y-1)-(y-3)

axis

x = - 2 y + y (y - 2) - 2 y (y - 1) - (y - 3)

y = - \frac{3}{2}

Solution steps

x = - 2 y + y (y - 2) - 2 y (y - 1) - (y - 3)

Rewrite

x = - 2 y + y (y - 2) - 2 y (y - 1) - (y - 3)

in the standard form

4 (- \frac{1}{4}) (x - \frac{21}{4}) = (y - (- \frac{3}{2}))^{2}

Therefore parabola properties are:

(h, k) = (\frac{21}{4}, - \frac{3}{2}), p = - \frac{1}{4}

Parabola is of the form

4 p (x - h) = (y - k)^{2}

and is symmetric around the

x

-axis

Axis of symmetry is a line parallel to the

x

-axis which intersects the vertex:

y = - \frac{3}{2}

y = - 0.5 x^{2} + 5.5

y = \frac{1}{2} x^{2} + 9 x + 8

x = (y - 7)^{2} + 1

y = x^{2} + 8

x^{2} + 10 x - 2 y + 21 = 0

What is the axis x=-2y+y(y-2)-2y(y-1)-(y-3) ?
The axis x=-2y+y(y-2)-2y(y-1)-(y-3) is y=-3/2