What is the axis 4x=y^2-4y ?

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

axis 4x=y^2-4y

axis

4 x = y^{2} - 4 y

y = 2

Solution steps

4 x = y^{2} - 4 y

Rewrite

4 x = y^{2} - 4 y

in the standard form

4 \cdot 1 \cdot (x - (- 1)) = (y - 2)^{2}

Therefore parabola properties are:

(h, k) = (- 1, 2), p = 1

Parabola is of the form

4 p (x - h) = (y - k)^{2}

and is symmetric around the

x

-axis

Axis of symmetry is a line parallel to the

x

-axis which intersects the vertex:

y = 2

3 x^{2} + 19 y = 0

y = 3 x^{2} + 6 x + 10

F (x) = 2 x^{2} + 2 x + 3

y = 10 (x - 6)^{2} + 5

y = 11 x - x^{2}