What is the axis y=x^2+8x+3 ?

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

axis y=x^2+8x+3

axis

y = x^{2} + 8 x + 3

x = - 4

Solution steps

y = x^{2} + 8 x + 3

Rewrite

y = x^{2} + 8 x + 3

in the standard form

4 \cdot \frac{1}{4} (y - (- 13)) = (x - (- 4))^{2}

Therefore parabola properties are:

(h, k) = (- 4, - 13), p = \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = - 4

y = x^{2} + 3 x

y = \frac{5 x + 3 - x ^{2}}{3}

y = 8 x - x^{2} - 17

y = 10 + 5 x - x^{2}

y = x^{2} + 18 x + 81