What is the axis y=(x+8)(x-8) ?

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axis y=(x+8)(x-8)

axis

y = (x + 8) (x - 8)

x = 0

Solution steps

y = (x + 8) (x - 8)

Rewrite

y = (x + 8) (x - 8)

in the standard form

4 \cdot \frac{1}{4} (y - (- 64)) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, - 64), p = \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 0

y = - x^{2} - x + 6

(x - 1)^{2} = - 20 (y - 4)

y = 4 x^{2} - 9

y = x^{2} - 20 x

y = x^{2} - 6 x + 13