What is the axis y=4-5x^2 ?

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axis y=4-5x^2

axis

y = 4 - 5 x^{2}

x = 0

Solution steps

y = 4 - 5 x^{2}

Rewrite

y = 4 - 5 x^{2}

in the standard form:

4 (- \frac{1}{20}) (y - 4) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 4), p = - \frac{1}{20}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 0

y = (x - 6) (x - 5)

(x + 1)^{2} = 2 (y + 2)

y = x^{2} + 81

(y - 1)^{2} = - 16 (x - 1)

y = \frac{- 7 + 2 x ^{2} - 4 x}{3}