What is the axis x=-1/4 (y+2)^2 ?

The axis x=-1/4 (y+2)^2 is y=-2

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axis x=-1/4 (y+2)^2

axis

x = - \frac{1}{4} (y + 2)^{2}

y = - 2

Solution steps

x = - \frac{1}{4} (y + 2)^{2}

Rewrite

x = - \frac{1}{4} (y + 2)^{2}

in the standard form:

4 (- 1) (x - 0) = (y - (- 2))^{2}

Therefore parabola properties are:

(h, k) = (0, - 2), p = - 1

Parabola is of the form

4 p (x - h) = (y - k)^{2}

and is symmetric around the

x

-axis

Axis of symmetry is a line parallel to the

x

-axis which intersects the vertex:

y = - 2

y = x^{2} - 6 x + 18

x + 5 + (y - 3)^{2} = 0

y = - x^{2} + 1

y = 4 x^{2} - 40 x + 98

y = x^{2} + x - 24