What is (x^2)/(100)+(y^2)/(64)=1 ?

The solution to (x^2)/(100)+(y^2)/(64)=1 is Ellipse with (h,k)=(0,0),a=10,b=8

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(x^2)/(100)+(y^2)/(64)=1

\frac{x ^{2}}{100} + \frac{y ^{2}}{64} = 1

(h, k) = (0, 0), a = 10, b = 8

Solution steps

\frac{x ^{2}}{100} + \frac{y ^{2}}{64} = 1

Rewrite

\frac{x ^{2}}{100} + \frac{y ^{2}}{64} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{1 0 ^{2}} + \frac{( y - 0 ) ^{2}}{8 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 10, b = 8

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 10, b = 8

4 x^{2} - 20 x - 24 y + 97 = 0

x^{2} + y^{2} = 16

9 x^{2} + 4 y^{2} + 36 x - 24 y + 36 = 0

y = - \frac{x ^{2}}{10} + \frac{9 x}{10} + \frac{11}{5}

\frac{x ^{2}}{4} - \frac{y ^{2}}{4} = 1

What is (x^2)/(100)+(y^2)/(64)=1 ?
The solution to (x^2)/(100)+(y^2)/(64)=1 is Ellipse with (h,k)=(0,0),a=10,b=8