What is the axis y= 2/3 (x-1)^2 ?

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axis y= 2/3 (x-1)^2

axis

y = \frac{2}{3} (x - 1)^{2}

x = 1

Solution steps

y = \frac{2}{3} (x - 1)^{2}

Rewrite

y = \frac{2}{3} (x - 1)^{2}

in the standard form:

4 \cdot \frac{3}{8} (y - 0) = (x - 1)^{2}

Therefore parabola properties are:

(h, k) = (1, 0), p = \frac{3}{8}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 1

x = y^{2} - 1

y = x^{2} - 8 x + 5

y = - (x - 6)^{2} + 1

y = \frac{3}{2} x^{2}

y = \frac{1}{5} x^{2} - \frac{8}{5} x + \frac{1}{5}