What is the axis y=6x^2+5x+3 ?

The axis y=6x^2+5x+3 is x=-5/12

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axis y=6x^2+5x+3

axis

y = 6 x^{2} + 5 x + 3

x = - \frac{5}{12}

Solution steps

y = 6 x^{2} + 5 x + 3

Rewrite

y = 6 x^{2} + 5 x + 3

in the standard form

4 \cdot \frac{1}{24} (y - \frac{47}{24}) = (x - (- \frac{5}{12}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{5}{12}, \frac{47}{24}), p = \frac{1}{24}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = - \frac{5}{12}

y = 6 x^{2} + 5 x + 7

9 x^{2} + 24 x + 72 y + 16 = 0

y = x^{2} + 36

y^{2} = 24 x

y = 5 x^{2} - 7 x - 6