What is the axis x=2y^2 ?

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axis x=2y^2

axis

x = 2 y^{2}

y = 0

Solution steps

x = 2 y^{2}

Rewrite

x = 2 y^{2}

in the standard form:

4 \cdot \frac{1}{8} (x - 0) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = \frac{1}{8}

Parabola is of the form

4 p (x - h) = (y - k)^{2}

and is symmetric around the

x

-axis

Axis of symmetry is a line parallel to the

x

-axis which intersects the vertex:

y = 0

y = (5 - x) (2 x - 3)

y = 3 x^{2} - 15 x + 6

x^{2} = - 16 y

y = 6 x^{2} - 12 x

y = + x^{2} + 3 x + 14