What is the axis y=x^2+3x+1 ?

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

axis y=x^2+3x+1

axis

y = x^{2} + 3 x + 1

x = - \frac{3}{2}

Solution steps

y = x^{2} + 3 x + 1

Rewrite

y = x^{2} + 3 x + 1

in the standard form

4 \cdot \frac{1}{4} (y - (- \frac{5}{4})) = (x - (- \frac{3}{2}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{3}{2}, - \frac{5}{4}), p = \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = - \frac{3}{2}

y = x^{2} + x + 1

y = 3 (x - 1)^{2} - 2

x = (y + 1)^{2} + 1

y = - 4 x^{2} + 183 x - 1247

y^{2} + 8 x + 4 y + 20 = 0