What is the axis y=x^2-3x-1 ?

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axis y=x^2-3x-1

axis

y = x^{2} - 3 x - 1

x = \frac{3}{2}

Solution steps

y = x^{2} - 3 x - 1

Rewrite

y = x^{2} - 3 x - 1

in the standard form

4 \cdot \frac{1}{4} (y - (- \frac{13}{4})) = (x - \frac{3}{2})^{2}

Therefore parabola properties are:

(h, k) = (\frac{3}{2}, - \frac{13}{4}), p = \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = \frac{3}{2}

x^{2} - 2 x + 36 y + 28 = 0

y = (x + 1) (x - 5)

x = + (y - 4)^{2} - 5

y = (x - 15)^{2}

x^{2} + 20 y = 0