What is the axis y=+x^2+3 ?

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

axis y=+x^2+3

axis

y = + x^{2} + 3

x = 0

Solution steps

y = x^{2} + 3

Rewrite

y = x^{2} + 3

in the standard form:

4 \cdot \frac{1}{4} (y - 3) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 3), p = \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 0

y = + (8 - x) (3 x + 2)

y = 4 + 2 x - x^{2}

y = - \frac{2}{5} x^{2} + 4 x

y = - x^{2} - 6 \cdot x + 7

y = x^{2} - 3 x + 5