What is the axis 30x^2+90x+y+64=0 ?

The axis 30x^2+90x+y+64=0 is x=-3/2

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axis 30x^2+90x+y+64=0

axis

30 x^{2} + 90 x + y + 64 = 0

x = - \frac{3}{2}

Solution steps

30 x^{2} + 90 x + y + 64 = 0

Rewrite

30 x^{2} + 90 x + y + 64 = 0

in the standard form

4 (- \frac{1}{120}) (y - \frac{7}{2}) = (x - (- \frac{3}{2}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{3}{2}, \frac{7}{2}), p = - \frac{1}{120}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = - \frac{3}{2}

y = (x - 7) (x - 9)

y = (3 x - 4) (4 x - 3) - 2 x

y = \frac{1}{2} x^{2} + x - 1

y = x^{2} - 15 x

y = \frac{3}{2} (x - 4)^{2} + 3