What is the axis x=(y-2)^2+3 ?

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axis x=(y-2)^2+3

axis

x = (y - 2)^{2} + 3

y = 2

Solution steps

x = (y - 2)^{2} + 3

Rewrite

x = (y - 2)^{2} + 3

in the standard form:

4 \cdot \frac{1}{4} (x - 3) = (y - 2)^{2}

Therefore parabola properties are:

(h, k) = (3, 2), p = \frac{1}{4}

Parabola is of the form

4 p (x - h) = (y - k)^{2}

and is symmetric around the

x

-axis

Axis of symmetry is a line parallel to the

x

-axis which intersects the vertex:

y = 2

y = + (3 - 2 x) (6 - x)

y^{2} - 16 x = 0

y = (x + 4)^{2} - 9

x = - \frac{( y + 3 ) ^{2}}{20} + 1

y = (x + 8)^{2} + 4 (x + 9) + 1