What is the axis y=x^2-11x+10 ?

The axis y=x^2-11x+10 is x= 11/2

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axis y=x^2-11x+10

axis

y = x^{2} - 11 x + 10

x = \frac{11}{2}

Solution steps

y = x^{2} - 11 x + 10

Rewrite

y = x^{2} - 11 x + 10

in the standard form

4 \cdot \frac{1}{4} (y - (- \frac{81}{4})) = (x - \frac{11}{2})^{2}

Therefore parabola properties are:

(h, k) = (\frac{11}{2}, - \frac{81}{4}), p = \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = \frac{11}{2}

y^{2} + x - 10 y + 29 = 0

2 x^{2} + 8 x - 4 y + 12 = 0

y = 9 - (x - 2)^{2}

y^{2} + 8 x + 2 y + 33 = 0

y = 3 x^{2} - 6 x - 2